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Question
Factorise : 4a2b - 9b3
Sum
Solution
4a2b - 9b3
= b( 4a2 - 9b2 )
= b[ (2a)2 - (3b)2 ]
= b( 2a - 3b )( 2a + 3b ) [ ∵ a2 - b2 = ( a + b )( a - b )]
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Method of Factorisation : Difference of Two Squares
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