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Factorise : (X2 + 4y2 - 9z2)2 - 16x2y2 - Mathematics

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Question

Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2

Sum

Solution

(x2 + 4y2 - 9z2)2 - 16x2y2

= (x2 + 4y2 - 9z2)2 - ( 4xy )2

= ( x2 + 4y2 - 9z2 - 4xy )( x2 + 4y2 - 9z2 + 4xy )      [ ∵ a2 - b2 = ( a + b )( a - b )]

= ( x2 + 4y2 - 4xy - 9z2 )( x2 + 4y2 + 4xy - 9z2 )

= [( x - 2y )2 - (3z)2 ][ ( x + 2y )2 - (3z)2 ]

= [( x - 2y ) - 3z ][( x - 2y ) + 3z ][( x + 2y ) - 3z ][( x + 2y ) + 3z ]

= [ x - 2y - 3z ][ x - 2y + 3z ][ x + 2y - 3z ][ x + 2y + 3z ]

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Method of Factorisation : Difference of Two Squares
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Chapter 5: Factorisation - Exercise 5 (C) [Page 73]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 5 Factorisation
Exercise 5 (C) | Q 23 | Page 73
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