Advertisements
Advertisements
Question
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
Sum
Solution
4x2 - 12ax - y2 - z2 - 2yz + 9a2
= (4x2 - 12ax + 9a2) - (y2 + z2 + 2yz)
= (2x - 3a)2 - (y + z)2
= [(2x - 3a) + (y + z)][(2x - 3a) - (y + z)]
= (2x - 3a + y + z)(2x - 3a - y - z).
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : 4a2b - 9b3
Factorise : a2 - b2 - (a + b) 2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise : a2 ( b + c) - (b + c)3
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
4xy - x2 - 4y2 + z2
Factorise the following:
(x + y)3 - x - y
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
