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Question
Factorise the following:
(2a - b)2 -9(3c - d)2
Sum
Solution
(2a - b)2 - 9(3c - d)2
= (2a - b)2 - [3(3c - d)]2
= [(2a - b) - 3(3c - d)][(2a - b) + 3(3c - d)]
= (2a - b - 9c + 3d)(2a - b + 9c - 3d).
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Method of Factorisation : Difference of Two Squares
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