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Question
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Sum
Solution
`"m"^2 - (1)/(9)"n"^2`
= `"m"^2 - (1/3"n")^2`
=`("m" - 1/3"n")("m" + 1/3"n")`.
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Method of Factorisation : Difference of Two Squares
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