Question

Factorize  a³ x³ - 3a2bx² + 3ab² x - b³

Answer 1

= (ax)³ - 3(ax)² × b + 3(ax)b² - b³

= (ax - b)³    [∵  a² - 3a²b + 3ab² - b³ = (a - b)³ ]

= (ax - b)(ax - b)(ax - b)

∴ a³ x³ - 3a²bx² + 3ab² x - b³  = (ax - b)(ax - b)(ax - b)