Advertisements
Advertisements
प्रश्न
Factorize `x^2 + 6sqrt2x + 10`
उत्तर
Splitting middle term
`= x^2 + 5sqrt2x + sqrt2x + 10` [∵ `6sqrt2 =5sqrt2 + sqrt2` and `5sqrt2 xx sqrt2 = 10`]
`= x(x + 5sqrt2) + sqrt2(x + 5sqrt2)`
`= (x + 5sqrt2)(x + sqrt2)`
`∴ x^2 + 6sqrt2x + 10 = (x + 5sqrt2)(x + sqrt2)`
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Number 5 added to three times the product of numbers m and n.
Factorize (a - b + c)2 + (b - c + a)2 + 2(a - b + c) (b - c + a)
Factorize `2x^2 + 3sqrt5x + 5`
Factorize the following expressions:
x3y3 + 1
Factorize x3 + 8y3 + 6x2 y +12xy2
The expression x4 + 4 can be factorized as
Evaluate: (a2 + 2ab + b2)(a + b)
Multiply: (2x + 3y)(2x - 3y)
Divide: 8a2 + 4a - 60 by 2a - 5
If x = 2 and y = 3, then find the value of the following expressions
x + y