Advertisements
Advertisements
प्रश्न
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.
उत्तर
No. of circular scale divisions = 200
Pitch = 1 mm
Least count (L.C.) = `"Pitch"/"No. of circular divisions"`
= `(1 "mm")/200`
= 0.005 mm
L.C. = 0.0005 cm
Main scale reading = 5 mm = 0.5 cm
(C.S.D.) circular scale reading = 34 divisions
Observed diameter of wire = Main scale reading + L.C. × C.S.D.
= 0.5 + 0.0005 × 34
= 0.5 + 0.0170
= 0.5170 cm
Redius of wire = `"diameter"/2`
= `0.5170/2`
= 0.2585 cm
APPEARS IN
संबंधित प्रश्न
Define the term 'Vernier constant'.
Describe the procedure to measure the diameter of a wire with the help of a screw gauge.
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 100
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 1000
Who invented vernier callipers?
What is the function of ratchet in the screw gauge?
How the backlash error is avoided?
State whether the following statement is true or false by writing T/F against it.
The diameter of a wire can be measured more accurately by using vernier calipers than by a screw gauge.
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
