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प्रश्न
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
उत्तर
Number of circular scale divisions = 100
Distance moved by spindle (screw) = 2.5 mm
No. of complete rotations given = 5
(1) Pitch = `"Distance moved by screw on sleeve"/"No. of complete rotations"`
= `2.5/5`
= 0.5 mm
= 0.05 cm
(2) Least count = `"Pitch"/"No. of circular scale divisions"`
= `0.05/100` cm
= 0.0005 cm
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संबंधित प्रश्न
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
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