Advertisements
Advertisements
प्रश्न
Find A as required:
The least number 567A is divisible by 3
उत्तर
A number is divisible by 3 if the sum of its digits is divisible by 3
Sum of digits of 567A = 5 + 6 + 7 + A
= 18 + A
∴ 18 is divisible by 3
∴ A maybe 0
The number will be 5670
APPEARS IN
संबंधित प्रश्न
If 31z5 is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?
If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?
If x is a digit such that the number \[\overline{{18x71}}\] is divisible by 3, find possible values of x.
Given that the number \[\overline{{67y19}}\] is divisible by 9, where y is a digit, what are the possible values of y?
Find which of the following numbers are divisible by 3:
(i) 261
(ii) 777
(iii) 6657
(iv) 2574
Find the dates of any month in a calendar which are divisible by both 2 and 3.
To play this game, everyone stands in a circle. One player calls out ‘one’. The next player says ‘two’ and so on. A player who has to call out 3 or a number that can be divided by 3 has to say ‘Meow’ instead of the number. One who forgets to say ‘Meow’ is out of the game. The last player left is the winner.
- Which numbers did you replace with ‘Meow’?
3, 6, 9 .........
Let abc be a three digit number. Then abc + bca + cab is not divisible by ______.
If the sum of digits of a number is divisible by three, then the number is always divisible by ______.
Number of the form 3N + 2 will leave remainder 2 when divided by 3.
