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Question
Find A as required:
The least number 567A is divisible by 3
Solution
A number is divisible by 3 if the sum of its digits is divisible by 3
Sum of digits of 567A = 5 + 6 + 7 + A
= 18 + A
∴ 18 is divisible by 3
∴ A maybe 0
The number will be 5670
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