Advertisements
Advertisements
Question
3134673 is divisible by 3 and ______.
Solution
3134673 is divisible by 3 and 9.
Explanation:
3134673 is divisible by 3 and 9 as sum of the digits, 3 + 1 + 3 + 4 + 6 + 7 + 3 = 27 is divisible by both 3 and 9.
APPEARS IN
RELATED QUESTIONS
If 31z5 is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?
Given that the number \[\overline{{67y19}}\] is divisible by 9, where y is a digit, what are the possible values of y?
Find the remainder when 51439786 is divided by 3. Do this without performing actual division.
Find the remainder when 51439786 is divided by 3. Do this without performing actual division.
Which of the following statement is true?
If a number is divisible by 9, it must be divisible by 3.
Find which of the following numbers are divisible by 3:
(i) 261
(ii) 777
(iii) 6657
(iv) 2574
28×6 a multiple of 3?
The least number that should be added to 57 so that the sum is exactly divisible by 2, 3, 4 and 5 is __________
Find A as required:
The least number 567A is divisible by 3
Write the smallest digit and the greatest digit in the blank space of the following number so that the number formed is divisible by 3:
______ 6724