Advertisements
Advertisements
प्रश्न
Find AD, if:
उत्तर
In ΔBCA
∠ABC = ∠BAC = x
∠ACD = ∠BAC + ∠ABC ...[Exterior angle equal to two int. opp. angle]
60° = x + x
60° = 2x
x = 30°
In ΔADB
sin B = `("AD")/("AB")`
sin 30° = `("AD")/(100)`
`(1)/(2) = ("AD")/(100)`
AD = 50 m
APPEARS IN
संबंधित प्रश्न
Find 'x', if :
Find angle 'A' if:
Find AD, if :
Find AB.
In trapezium ABCD, as shown, AB // DC, AD = DC = BC = 20 cm and A = 60°. Find: distance between AB and DC.
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠ AED = 60° and ∠ ACD = 45°. Calculate: AB.
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠AED = 60° and ∠ACD = 45°. Calculate: AC
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
BC is `sqrt(3)` times of AB.
Find AB and BC, if:
Find PQ, if AB = 150 m, ∠ P = 30° and ∠ Q = 45°.
