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प्रश्न
Find the average magnitude of linear momentum of a helium molecule in a sample of helium gas at 0°C. Mass of a helium molecule = 6.64 × 10−27 kg and Boltzmann constant = 1.38 × 10−23 J K−1.
उत्तर
Here,
m = 6.64 × 10−27 kg
T = 273 K
\[\text { Average speed of the He atom is given by }\] \[ V_{avg} = \sqrt{\frac{8kT}{\pi m}}\]
\[ = \sqrt{\frac{8 \times 1 . 38 \times {10}^{- 23} \times 273}{3 . 14 \times 6 . 64 \times {10}^{- 27}}}\]
\[ = 1202 . 31\]
We know,
Momentum = m × Vavg
= 6.64 × 10−27 × 1201.35
= 7.97 × 10−24
= 8 × 10−24 kg-m/s
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