Advertisements
Advertisements
प्रश्न
Find if x = – 1 is a root of the equation 2x² – 3x + 1 = 0.
उत्तर
2x² – 3x + 1 = 0; x = -1.
Putting x = -1 in L.H.S. of equation
L.H.S. = 2(-1)2 - 3 x -1 + 1
= 2 + 3 + 1
= 6 ≠ 0 ≠ R.H.S.
Hence, x = -1 is not a root of the equation.
APPEARS IN
संबंधित प्रश्न
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx + 3 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
x2 - kx + 9 = 0
In each of the following determine the; value of k for which the given value is a solution of the equation:
kx2 + 2x - 3 = 0; x = 2
Find the discriminant of the following equations and hence find the nature of roots: 7x2 + 8x + 2 = 0
If α and β are the roots of the equation 2x2 – 3x – 6 = 0. The equation whose roots are `1/α` and `1/β` is:
The equation 12x2 + 4kx + 3 = 0 has real and equal roots, if:
Every quadratic equation has at least one real root.
State whether the following quadratic equation have two distinct real roots. Justify your answer.
(x – 1)(x + 2) + 2 = 0
Find the value of 'k' so that the quadratic equation 3x2 – 5x – 2k = 0 has real and equal roots.
If 4 is a root of equation x2 + kx – 4 = 0; the value of k is ______.