Advertisements
Advertisements
Question
Find if x = – 1 is a root of the equation 2x² – 3x + 1 = 0.
Solution
2x² – 3x + 1 = 0; x = -1.
Putting x = -1 in L.H.S. of equation
L.H.S. = 2(-1)2 - 3 x -1 + 1
= 2 + 3 + 1
= 6 ≠ 0 ≠ R.H.S.
Hence, x = -1 is not a root of the equation.
APPEARS IN
RELATED QUESTIONS
Solve the quadratic equation 2x2 + ax − a2 = 0 for x.
Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:
`3x^2 - 4sqrt3x + 4 = 0`
If the roots of the equation (c2 – ab) x2 – 2 (a2 – bc) x + b2 – ac = 0 in x are equal, then show that either a = 0 or a3 + b3 + c3 = 3abc
Find the value(s) of k so that the quadratic equation 3x2 − 2kx + 12 = 0 has equal roots ?
Solve the following quadratic equation using formula method only
`3"x"^2 + 2 sqrt 5x - 5 = 0 `
Solve the following quadratic equation using formula method only
`3"x"^2 - 5"x" + 25/12 = 0 `
If α and β are the roots of the equation 2x2 – 3x – 6 = 0. The equation whose roots are `1/α` and `1/β` is:
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
If 3 is a root of the quadratic equation x2 – px + 3 = 0 then p is equal to ______.
Solve the following quadratic equation:
x2 + 4x – 8 = 0
Give your Solution correct to one decimal place.
(Use mathematical tables if necessary.)