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Find the Largest Number Which Exactly Divides 280 and 1245 Leaving Remainders 4 and 3, Respectively. - Mathematics

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प्रश्न

Find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3, respectively.

उत्तर

The required number when divides 280 and 1245 leaves the remainder 4 and 3, this means 280 4 – 216 and 1245 – 3 = 1245 – 3 = 1242 are completely divisible by the number

∴ The required number = HCF of 276 and 1242

By applying Euclid’s division lemma

1242 = 276 × 4 + 138

276 = 138 × 2 + 0

∴ HCF = 138

Hence the required numbers is 138.

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पाठ 1: Real Numbers - Exercise 1.2 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 1 Real Numbers
Exercise 1.2 | Q 12 | पृष्ठ २८

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