Advertisements
Advertisements
प्रश्न
What is the largest number that divides 626, 3127 and 15628 and leaves remainders of 1, 2 and 3 respectively.
उत्तर
The required number when divides 626, 3127 and 15628, leaves remainder 1, 2 and 3.
This means 626 – 1 = 625, 3127 – 2 = 3125 and
15628 – 3 = 15625 are completely divisible by the number
∴ The required number = HCF of 625, 3125 and 15625
First consider 625 and 3125
By applying Euclid’s division lemma
3125 = 625 × 5 + 0
HCF of 625 and 3125 = 625
Now consider 625 and 15625
By applying Euclid’s division lemma
15625 = 625 × 25 + 0
∴ HCF of 625, 3125 and 15625 = 625
Hence required number is 625
APPEARS IN
संबंधित प्रश्न
Using Euclid's division algorithm, find the H.C.F. of (iii) 867 and 255
Show that the square of an odd positive integer is of the form 8q + 1, for some integer q.
Define HOE of two positive integers and find the HCF of the following pair of numbers:
475 and 495
Find the largest number which divides 438 and 606 leaving remainder 6 in each case.
Without actual division show that each of the following rational numbers is a non-terminating repeating decimal.
(i) `129/(2^2× 5^7 × 7^5)`
A circular field has a circumference of 360 km. Three cyclists start together and can cycle 48, 60 and 72 km a day, round the field. When will they meet again?
The sum of two prime number is always a prime number (True/ False).
If a and b are relatively prime numbers, then what is their HCF?
Show that the square of any positive integer cannot be of the form 5q + 2 or 5q + 3 for any integer q.
For any positive integer n, prove that n3 – n is divisible by 6.
