Advertisements
Advertisements
प्रश्न
Find the numbers such that the sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.
उत्तर
Let the first number be x and the second number be y.
Then, we have:
3x + y = 142 ……….(i)
4x - y = 138 ………(ii)
On adding (i) and (ii), we get
7x = 280
⇒ x = 40
On substituting x = 40 in (i), we get:
3 × 40 + y = 142
⇒ y = (142 – 120) = 22
⇒ y = 22
Hence, the first number is 40 and the second number is 22.
APPEARS IN
संबंधित प्रश्न
Find the value of k for which each of the following system of equations has infinitely many solutions :
2x + (k - 2)y = k
6x + (2k - 1)y - (2k + 5)
Find the value of k for which each of the following system of equations have no solution :
2x + ky = 11
5x − 7y = 5
Solve for x and y:
`3/x + 2/y = 12, 2/x + 3/y = 13`
Solve for x and y:
71x + 37y = 253, 37x + 71y = 287
Solve for x and y:
`a^2x + b^2y = c^2, b^2x + a^2y = d^2`
A lady has only 50-paisa coins and 25-paisa coins in her purse. If she has 50 coins in all totaling Rs.19.50, how many coins of each kind does she have?
The sum of the digits of a two-digit number is 15. The number obtained by interchanging the digits exceeds the given number by 9. Find the number.
A man invested an amount at 10% per annum simple interest and another amount at 10% per annum simple interest. He received an annual interest of Rs. 1350. But, if he had interchanged the amounts invested, he would have received Rs. 45 less. What amounts did he invest at different rates?
In a cyclic quadrilateral ABCD, it is given ∠A = (2x + 4)°, ∠B = (y + 3)°, ∠C = (2y + 10)° and ∠D = (4x – 5)°. Find the four angles.
If `2 /x + 3/y = 9/(xy) and 4/x + 9/y = 21/(xy)` find the values of x and y.
