Advertisements
Advertisements
प्रश्न
Find the area of triangles whose vertices are L(1, 1), M(−2, 2), N(5, 4)
उत्तर
Here, L(x1, y1) ≡ L(1, 1), M(x2, y2) ≡ M(–2, 2), N(x3, y3) ≡ N(5, 4)
Area of a triangle = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`
∴ A(ΔLMN) = `1/2|(1, 1, 1),(-2, 2, 1),(5, 4, 1)|`
= `1/2[1(2 - 4) - 1 (-2 - 5) + 1 (- 8 - 10)]`
= `1/2[1(-2) - 1( - 7) + 1 (- 18)]`
= `1/2(-2 + 7 - 18)`
= `-13/2`
Since, area cannot be negative.
∴ A(ΔLMN) = `13/2` sq. units
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle whose vertices are: (4, 5), (0, 7), (–1, 1)
Find the area of the triangle whose vertices are: (3, 2), (–1, 5), (–2, –3)
Find the area of the triangle whose vertices are: (0, 5), (0, – 5), (5, 0)
Find the value of k, if the area of the triangle with vertices at A(k, 3), B(–5, 7), C(–1, 4) is 4 square units.
Find the area of the quadrilateral whose vertices are A(–3, 1), B(–2, –2), C(4, 1), D(2, 3).
Find the value of k, if area of ΔPQR is 4 square units and vertices are P(k, 0), Q(4, 0), R(0, 2).
The maximum area of a right angled triangle with hypotenuse h is:
Find the area of triangle whose vertices are A ( -1,2), B (2,4), C (0,0)
Find the area of triangle whose vertices are A( -1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(−1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(−1, 2), B(2, 4), C(0, 0)
Find the area of triangles whose vertices are A(−1, 2), B(2, 4), C(0, 0).