मराठी

Find the area of triangles whose vertices are L(1, 1), M(−2, 2), N(5, 4) - Mathematics and Statistics

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प्रश्न

Find the area of triangles whose vertices are L(1, 1), M(−2, 2), N(5, 4)

बेरीज

उत्तर

Here, L(x1, y1) ≡ L(1, 1), M(x2, y2) ≡ M(–2, 2), N(x3, y3) ≡ N(5, 4)

Area of a triangle = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`

∴ A(ΔLMN) = `1/2|(1, 1, 1),(-2, 2, 1),(5, 4, 1)|`

= `1/2[1(2 - 4) - 1 (-2 - 5) + 1 (- 8 - 10)]`

= `1/2[1(-2) - 1( - 7) + 1 (- 18)]`

= `1/2(-2 + 7 - 18)`

= `-13/2`

Since, area cannot be negative.

∴ A(ΔLMN) = `13/2` sq. units

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Application of Determinants - Area of a Triangle Using Determinants
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पाठ 6: Determinants - MISCELLANEOUS EXERCISE - 6 [पृष्ठ ९५]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] 11 Standard Maharashtra State Board
पाठ 6 Determinants
MISCELLANEOUS EXERCISE - 6 | Q 7) iii) | पृष्ठ ९५
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