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प्रश्न
Find the distance between the line 4x + 3y + 4 = 0, and a point (7, −3)
उत्तर
Given point (x1, y1) = (7, – 3)
Given line 4x + 3y + 4 = 0
Required distance = `(4(7) + 3( - 3) + 4)/sqrt(4^2 + 3^2)`
= `(28 - 9 + 4)/sqrt(16 + 9)`
= `23/5`
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