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प्रश्न
Find the equation of the line whose X-intercept is 3 and which is perpendicular to the line 3x − y + 23 = 0.
उत्तर
Slope of the line 3x − y + 23 = 0 is `(-3)/(-1)` = 3.
Since the required line is perpendicular to this line, the slope of the line is `-1/3`.
Since x-intercept of the line is 3, the line is passing through the point (3, 0).
∴ The equation of the required line is
y − 0 = `-1/3(x - 3)`
∴ 3y = − x + 3
∴ x + 3y = 3
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