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प्रश्न
Find the HCF of 1260 and 7344 using Euclid's algorithm.
उत्तर
Since 7344 > 1260
7344 = 1260 × 5 + 1044
Since remainder ≠ 0
1260 = 1044 × 1 + 216
1044 = 216 × 4 + 180
216 = 180 × 1 + 36
180 = 36 × 5 +0
The remainder has now become zero.
∴ HCF of 1260 and 7344 is 36.
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