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प्रश्न
find the acute angle between the lines
x2 – 4xy + y2 = 0.
उत्तर
The given pair of lines are x2 – 4xy + y2 = 0
Comparing with ax2 + 2hxy + by2 = 0, we get
a = 1, h = –2, b = 1
`tantheta=|(2sqrt(h^2-ab))/(a+b)|=|(2sqrt(4-1))/(1+1)|`
`=|(2sqrt3)/2|`
`tantheta=sqrt3`
`theta=60^@ or pi/3`
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