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प्रश्न
Find the Median of the following distribution:
| x | 3 | 5 | 10 | 12 | 8 | 15 |
| f | 2 | 4 | 6 | 10 | 8 | 7 |
उत्तर
Arranging the terms in ascending order and preparing the cumulative frequency table:
| x | f | c.f. |
| 3 | 2 | 2 |
| 5 | 4 | 6 |
| 8 | 8 | 14 |
| 10 | 6 | 20 |
| 12 | 10 | 30 |
| 15 | 7 | 37 |
Here, n = 37 which is odd.
So Median = `(("n" + 1)/2)^"th" "term"`
= `((37 + 1)/2)^"th" "term"`
= `(38/2)^"th"`
= 19th term
Hence, Median is the value of the 9th term = 10.
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संबंधित प्रश्न
The marks obtained by 30 students in a class assignment of 5 marks are given below.
| Marks | 0 | 1 | 2 | 3 | 4 | 5 |
| No. of Students |
1 | 3 | 6 | 10 | 5 | 5 |
Calculate the mean, median and mode of the above distribution
Following are the lives in hours of 15 pieces of the components of aircraft engine. Find the median:
715, 724, 725, 710, 729, 745, 694, 699, 696, 712, 734, 728, 716, 705, 719.
The following is the distribution of height of students of a certain class in a certain city:
| Height (in cm): | 160 - 162 | 163 - 165 | 166 - 168 | 169 - 171 | 172 - 174 |
| No. of students: | 15 | 118 | 142 | 127 | 18 |
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Following is the distribution of I.Q. of loo students. Find the median I.Q.
| I.Q.: | 55 - 64 | 65 - 74 | 75 - 84 | 85 - 94 | 95 - 104 | 105 - 114 | 115 - 124 | 125 - 134 | 135 - 144 |
| No of Students: | 1 | 2 | 9 | 22 | 33 | 22 | 8 | 2 | 1 |
The following table gives the frequency distribution of married women by age at marriage:
| Age (in years) | Frequency |
| 15-19 | 53 |
| 20-24 | 140 |
| 25-29 | 98 |
| 30-34 | 32 |
| 35-39 | 12 |
| 40-44 | 9 |
| 45-49 | 5 |
| 50-54 | 3 |
| 55-59 | 3 |
| 60 and above | 2 |
Calculate the median and interpret the results.
If the median of the following data is 32.5, find the missing frequencies.
| Class interval: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | Total |
| Frequency: | f1 | 5 | 9 | 12 | f2 | 3 | 2 | 40 |
From the following data, find:
Upper quartile
25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83
From the following data, find:
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| Pocket expenses |
0 - 200 |
200 - 400 |
400 - 600 |
600 - 800 |
800 - 1000 |
1000 - 1200 |
1200 - 1400 |
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Then the median for the above data is?
The median of first 10 natural numbers is ______.
