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प्रश्न
Find the median of the given data: 35, 25, 34, 36, 45, 18, 28
उत्तर
Arranging the given data in ascending order 18, 25, 28, 34, 35, 36, 45.
Here the number of observations n = 7, which is odd.
∴ Median = `(("n" + 1)/2)^"th"` term
= `((7 + 1)/2)^"th"` term
= `(8/2)^"th"` term
= 4th term
Hence Median = 34
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संबंधित प्रश्न
Draw an ogive for the data given below and from the graph determine:
- the median marks
- the number of students who obtained more than 75% marks
Marks | No. of students |
0 – 9 | 5 |
10 – 19 | 9 |
20 – 29 | 16 |
30 – 39 | 22 |
40 – 49 | 26 |
50 – 59 | 18 |
60 – 69 | 11 |
70 – 79 | 6 |
80 – 89 | 4 |
90 – 99 | 3 |
The marks of 20 students in a test were as follows:
2, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19 and 20.
Calculate:
- the mean
- the median
- the mode
Following 10 observations are arranged in ascending order as follows.
2, 3, 5, 9, x + 1, x + 3, 14, 16, 19, 20
If the median of the data is 11, find the value of x.
Find the mean of the following frequency distribution by the short cut method :
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 9 | 12 | 15 | 10 | 14 |
Find the mean of the following frequency distribution by the step deviation method :
Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 | 120-140 |
Frequency | 12 | 24 | 52 | 88 | 66 | 42 | 16 |
Find the median of the following:
25, 34, 31, 23, 22, 26, 35, 29, 20, 32
The frequency distribution table below shows the height of 50 students of grade 10.
Heights (in cm) | 138 | 139 | 140 | 141 | 142 |
Frequency | 6 | 11 | 16 | 10 | 7 |
Find the median, the upper quartile and the lower quartile of the heights.
Find the mean of: 7, 10, 4 and 17
The median class for the given distribution is:
Class Interval | 1 - 5 | 6 - 10 | 11 - 15 | 16 - 20 |
Cumulative Frequency | 2 | 6 | 11 | 18 |
An incomplete frequency distribution is given below
Variate | Frequency |
10 – 20 | 12 |
20 – 30 | 30 |
30 – 40 | ? |
40 – 50 | 65 |
50 – 60 | 45 |
60 – 70 | 25 |
70 – 80 | 18 |
Total | 229 |
Median value is 46, the missing frequency is: