Advertisements
Advertisements
प्रश्न
Find the mean of the following frequency distribution by the short cut method :
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 9 | 12 | 15 | 10 | 14 |
उत्तर
Class Interval | xi | fi | A = 25 d = x - A |
`f_i d` |
0-10 | 5 | 9 | -20 | -180 |
10-20 | 15 | 12 | -10 | -120 |
20-30 | A = 25 | 15 | 0 | 0 |
30-40 | 35 | 10 | 10 | 100 |
40-50 | 45 | 14 | 20 | 280 |
Total | 60 | 80 |
`barx = A + (Σf_i d)/(Σf_i)`
`barx = 25 + 80/60`
`barx = 25 + 1.33`
`barx = 26.33`
`therefore` Mean = 26.33
APPEARS IN
संबंधित प्रश्न
The distribution given below shows the marks obtained by 25 students in an aptitude test. Find the mean, median and mode of the distribution.
Marks obtained | 5 | 6 | 7 | 8 | 9 | 10 |
No. of students | 3 | 9 | 6 | 4 | 2 | 1 |
Find the mean of the following frequency distribution by the step deviation method :
Class | 100-110 | 110-120 | 120-130 | 130-140 | 140-150 |
Frequency | 15 | 18 | 32 | 25 | 10 |
Draw a histogram for the following distribution and estimate the mode:
Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
No. of students | 3 | 7 | 15 | 24 | 16 | 8 | 5 | 2 |
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Marks(more than) | 90 | 80 | 70 | 60 | 50 | 40 | 30 | 20 | 10 | 0 |
No. of students | 6 | 13 | 22 | 34 | 48 | 60 | 70 | 78 | 80 | 80 |
The following data have been arranged in ascending order. If their median is 63, find the value of x.
34, 37, 53, 55, x, x + 2, 77, 83, 89 and 100.
Find the mean of: 3, 1, 5, 4, 4 and 7
Find the mean of: all prime numbers upto 30
Find the median of 80, 48, 66, 61, 75, 52, 45 and 70
The mean of five positive integers is twice their median. If four of the integers are 3, 4, 6, 9 and median is 6, then find the fifth integer
The median of the data 12, 14, 23, 25, 34, 11, 42, 45, 32, 22, 44 is ___________