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Question
Find the mean of the following frequency distribution by the short cut method :
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 9 | 12 | 15 | 10 | 14 |
Solution
Class Interval | xi | fi | A = 25 d = x - A |
|
0-10 | 5 | 9 | -20 | -180 |
10-20 | 15 | 12 | -10 | -120 |
20-30 | A = 25 | 15 | 0 | 0 |
30-40 | 35 | 10 | 10 | 100 |
40-50 | 45 | 14 | 20 | 280 |
Total | 60 | 80 |
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RELATED QUESTIONS
From the data given below, calculate the mean wage, correct to the nearest rupee.
Category | A | B | C | D | E | F |
Wages (Rs/day) | 50 | 60 | 70 | 80 | 90 | 100 |
No. of workers | 2 | 4 | 8 | 12 | 10 | 6 |
- If the number of workers in each category is doubled, what would be the new mean wage?
- If the wages per day in each category are increased by 60%; what is the new mean wage?
- If the number of workers in each category is doubled and the wages per day per worker are reduced by 40%, what would be the new mean wage?
The following table gives the weekly wages of workers in a factory.
Weekly wages (Rs) | No. of workers |
50 – 55 | 5 |
55 – 60 | 20 |
60 – 65 | 10 |
65 – 70 | 10 |
70 – 75 | 9 |
75 – 80 | 6 |
80 – 85 | 12 |
85 – 90 | 8 |
Calculate the mean by using:
Short-cut method
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Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
Frequency | 7 | p | 10 | 9 | 13 |
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- the median marks
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0 – 9 | 5 |
10 – 19 | 9 |
20 – 29 | 16 |
30 – 39 | 22 |
40 – 49 | 26 |
50 – 59 | 18 |
60 – 69 | 11 |
70 – 79 | 6 |
80 – 89 | 4 |
90 – 99 | 3 |
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