Advertisements
Advertisements
प्रश्न
Find the minors and cofactors of all the elements of the following determinant.
`|(1,-3,2),(4,-1,2),(3,5,2)|`
उत्तर
Minor of 1 is M11 = `|(-1,2),(5,2)|` = -2 – 10 = -12
Minor of -3 is M12 = `|(4,2),(3,2)|` = 8 - 6 = 2
Minor of 2 is M13 = `|(4,-1),(3,5)|` = 20 + 3 = 23
Minor of 4 is M21 = `|(-3,2),(5,2)|` = - 6 - 10 = - 16
Minor of -1 is M22 = `|(1,2),(3,2)|` = 2 - 6 = - 4
Minor of 2 is M23 = `|(1,-3),(3,5)|` = 5 + 9 = 14
Minor of 3 is M31 = `|(-3,2),(-1,2)|` = - 6 + 2 = - 4
Minor of 5 is M32 = `|(1,2),(4,2)|` = 2 - 8 = - 6
Minor of 2 is M33 = `|(1,-3),(4,-1)|`= - 1 + 12 = 11
Cofactor of 1 is A11 = (-1)1+1 M11 = -12
Cofactor of -3 is A12 = (-1)1+2 M12 = -2
Cofactor of 2 is A13 = (-1)1+3 M13 = 23
Cofactor of 4 is A21 = (-1)2+1 M21 = -1 × -16 = 16
Cofactor of -1 is A22 = (-1)2+2 M22 = -4
Cofactor of 2 is A23 = (-1)2+3 M23 = -14
Cofactor of 3 is A31 = (-1)3+1 M31 = -4
Cofactor of 5 is A32 = (-1)3+2 M32 = -1 × -6 = 6
Cofactor of 2 is A33 = (-1)3+3 M33 = 11
APPEARS IN
संबंधित प्रश्न
If A is a square matrix of order 3 and |A| = 3 then |adj A| is equal to:
If `|(4,3),(3,1)|` = -5 then the value of `|(20,15),(15,5)|` is:
Evaluate the following determinant:
`|(4,7),(-7,0)|`
Without expanding evaluate the following determinant.
`|(1,a,a + c),(1,b,c + a),(1,c,a + b)|`
Evaluate the following determinant :
`|(3,-5,2),(1,8,9),(3,7,0)|`
Without expanding evaluate the following determinant.
`|(1,a,a+c),(1,b,c+a),(1,c,a+b)|`
Find the value of x if `|(x,-1,2),(2x,1,-3),(3,-4,5)|` = 29
Evaluate the following determinant:
`|(a,h,g),(h,b,f),(g,f,c)|`
Evaluate the following determinants:
`|(4, 7),(-7, 0)|`
Find the value of x if `|(x, 2x, 3),(-1, 1, -4),(3, -3, 5)|` = 29