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प्रश्न
Find the period and amplitude of y = `- sin(1/3 x)`
उत्तर
y = `- sin(1/3 x)`
a = –1
b = `1/3`
∴ Amplitude = |a| = |–1| = 1
Period = `(2pi)/|"b"|`
= `(2pi)/|1/3|`
= 3(2π)
= 6π
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