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Chapters
2: Complex Numbers
3: Theory of Equations
▶ 4: Inverse Trigonometric Functions
5: Two Dimensional Analytical Geometry-II
6: Applications of Vector Algebra
7: Applications of Differential Calculus
8: Differentials and Partial Derivatives
9: Applications of Integration
10: Ordinary Differential Equations
11: Probability Distributions
12: Discrete Mathematics
![Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board chapter 4 - Inverse Trigonometric Functions Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board chapter 4 - Inverse Trigonometric Functions - Shaalaa.com](/images/mathematics-volume-1-and-2-english-class-12-tn-board_6:5f2b1b2038084cf381bfa42c826a928c.jpg)
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Solutions for Chapter 4: Inverse Trigonometric Functions
Below listed, you can find solutions for Chapter 4 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Mathematics - Volume 1 and 2 [English] Class 12 TN Board.
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board 4 Inverse Trigonometric Functions Exercise 4.1 [Page 137]
Find all the values of x such that – 10π ≤ x ≤ 10π and sin x = 0
Find all the values of x such that Find all the values of x such that −3π ≤ x ≤ 3π and sin x = −1
Find the period and amplitude of y = sin 7x
Find the period and amplitude of y = `- sin(1/3 x)`
Find the period and amplitude of y = 4 sin(– 2x)
Sketch the graph of y = `sin(1/3 x)` for 0 ≤ x ≤ 6π
Find the value of `sin^-1(sin((2pi)/3))`
Find the value of `sin^-1 (sin((5pi)/4))`
For what value of x does sin x = sin–1x?
Find the domain of the following
`f(x) = sin^-1 ((x^2 + 1)/(2x))`
Find the domain of the following
`g(x) = 2sin^-1(2x - 1) - pi/4`
Find the value of `sin^-1(sin (5pi)/9 cos pi/9 + cos (5pi)/9 sin pi/9)`
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board 4 Inverse Trigonometric Functions Exercise 4.2 [Pages 142 - 143]
Find all values of x such that – 6π ≤ x ≤ 6π and cos x = 0
Find all values of x such that – 5π ≤ x ≤ 5π and cos x = 1
State the reason for `cos^-1 [cos(- pi/6)] ≠ - pi/6`
Is cos–1(– x) = π – cos–1 true? justify your answer
Find the principal value of `cos^-1 (1/2)`
Find the value of `2cos^-1 (1/2) + sin^-1 (1/2)`
Find the value of `cos^-1(1/2) + sin^-1( - 1)`
Find the value of `cos-1 [cos pi/7 cos pi/17 - sin pi/7 sin pi/17]`
Find the domain of `f(x) = sin^-1 ((|x| - 2)/3) + cos^-1 ((1 - |x|)/4)`
Find the domain of `g(x) = sin^-1x + cos^-1x`
For what value of x, the inequality `pi/2 < cos^-1 (3x - 1) < pi` holds?
Find the value of `cos[cos^-1 (4/5) + sin^-1(4/5)]`
Find the value of `cos^-1(cos((4pi)/3)) + cos^-1 (cos((5pi)/4))`
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board 4 Inverse Trigonometric Functions Exercise 4.3 [Pages 147 - 148]
Find the domain of the following functions:
`tan^-1 (sqrt(9 - x^2))`
Find the domain of the following functions:
`1/2 tan^-1 (1 - x^2) - pi/4`
Find the value of `tan^-1(tan (5pi)/4)`
Find the value of `tan^-1 (tan(- pi/6))`
Find the value of `tan(tan^-1((7pi)/4))`
Find the value of `tan(tan^-1(1947))`
Find the value of `tan(tan^-1(- 0.2021))`
Find the value of `tan(cos^-1 (1/2) - sin^-1 (- 1/2))`
Find the value of `sin(tan^-1 (1/2) - cos^-1 (4/5))`
Find the value of `cos(sin^-1 (4/5) - tan^-1 (3/4))`
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board 4 Inverse Trigonometric Functions Exercise 4.4 [Pages 154 - 155]
Find the principal value of `sec^-1 (2/sqrt(3))`
Find the principal value of `cot^-1 (sqrt(3))`
Find the principal value of `"cosec"^-1 (- sqrt(2))`
Find the value of `tan^-1 (sqrt(3)) - sec^-1 (- 2)`
Find the value of `sin^-1 (- 1) + cos^-1 (1/2) + cot^-1 (2)`
Find the value of `cot^-1(1) + sin^-1 (- sqrt(3)/2) - sec^-1 (- sqrt(2))`
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board 4 Inverse Trigonometric Functions Exercise 4.5 [Page 166]
Find the value, if it exists. If not, give the reason for non-existence
`sin^-1 (cos pi)`
Find the value, if it exists. If not, give the reason for non-existence
`tan^-1(sin(- (5pi)/2))`
Find the value, if it exists. If not, give the reason for non-existence
`sin^-1 [sin 5]`
Find the value of the expression in terms of x, with the help of a reference triangle
sin (cos–1(1 – x))
Find the value of the expression in terms of x, with the help of a reference triangle
cos (tan–1 (3x – 1))
Find the value of the expression in terms of x, with the help of a reference triangle
`tan(sin^-1(x + 1/2))`
Find the value of `sin^-1[cos(sin^-1 (sqrt(3)/2))]`
Find the value of `cot[sin^-1 3/5 + sin^-1 4/5]`
Find the value of `tan(sin^-1 3/5 + cot^-1 3/2)`
Prove that `tan^-1 2/11 + tan^-1 7/24 = tan^-1 1/2`
Prove that `sin^-1 3/5 - cos^-1 12/13 = sin^-1 16/65`
Prove that `tan^-1x + tan^-1y + tan^-1z = tan^-1[(x + y + z - xyz)/(1 - xy - yz - zx)]`
If tan–1x + tan–1y + tan–1z = π, show that x + y + z = xyz
Prove that `tan^-1x + tan^-1 (2x)/(1 - x^2) = tan^-1 (3x - x^3)/(1 - 3x^2), |x| < 1/sqrt(3)`
Simplify: `tan^-1 x/y - tan^-1 (x - y)/(x + y)`
Solve: `sin^-1 5/x + sin^-1 12/x = pi/2`
Solve: `tan^-1x = cos^-1 (1 - "a"^2)/(1 + "a"^2) - cos^-1 (1 - "b"^2)/(1 + "b"^2), "a" > 0, "b" > 0`
Solve: `2tan^-1 (cos x) = tan^-1 (2"cosec" x)`
Solve: `cot^-1 x - cot^-1 (x + 2) = pi/12, x > 0`
Find the number of solutions of the equation `tan^-1 (x - 1) + tan^-1x + tan^-1(x + 1) = tan^-1(3x)`
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board 4 Inverse Trigonometric Functions Exercise 4.6 [Pages 166 - 168]
MCQ
Choose the correct alternative:
The value of sin–1(cos x), 0 ≤ x ≤ π is
`pi - x`
`x - pi/2`
`pi/2 - x`
`x - pi`
Choose the correct alternative:
If `sin^-1x + sin^-1y = (2pi)/3` ; then `cos^-1x + cos^-1y` is equal to
`(2pi)/3`
`pi/3`
`pi/6`
`pi`
Choose the correct alternative:
`sin^-1 3/5 - cos^-1 13/13 + sec^-1 5/3 - "cosec"^-1 13/12` is equal to
`2pi`
`pi`
0
`tan^-1 12/65`
Choose the correct alternative:
If sin–1x = 2sin–1 α has a solution, then
`|alpha| ≤ 1/sqrt(2)`
`|alpha| ≥ 1/sqrt(2)`
`|alpha| < 1/sqrt(2)`
`|alpha| > 1/sqrt(2)`
Choose the correct alternative:
`sin^-1(cos x) = pi/2 - x` is valid for
`pi ≤ x ≤ 0`
0 ≤ x ≤ π
`- pi/2 ≤ x ≤ pi/2`
`- pi/4 ≤ x ≤ (3pi)/4`
Choose the correct alternative:
If sin-1 x + sin-1 y + sin-1 z = `(3pi)/2`, the value of show that `x^2017 + y^2018 + z^2019 - 9/(x^101 + y^101 + z^101)` is
0
1
2
3
Choose the correct alternative:
If `cot^-1x = (2pi)/5` for some x ∈ R, the value of tan-1 x is
`- pi/10`
`pi/5`
`pi/10`
`- pi/5`
Choose the correct alternative:
The domain of the function defined by f(x) = `sin^-1 sqrt(x - 1)` is
[1, 2]
[– 1, 1]
[0, 1]
[– 1, 0]
Choose the correct alternative:
If x = `1/5`, the value of `cos(cos^-1x + 2sin^-1x)` is
`- sqrt(24/25)`
`sqrt(24/25)`
`1/5`
`- 1/5`
Choose the correct alternative:
`tan^-1 (1/4) + tan^-1 (2/9)` is equal to
`1/2 cos^-1 (3/5)`
`1/2 sin^-1 (3/5)`
`1/2 tan^-1 (3/5)`
`tan^-1 (1/2)`
Choose the correct alternative:
If the function `f(x) = sin^-1 (x^2 - 3)`, then x belongs to
[– 1, 1]
`[sqrt(2), 2]`
`[-2, sqrt(2)] ∪ [sqrt(2), 2]`
`[- 2 -sqrt(2)]`
Choose the correct alternative:
If cot–12 and cot–13 are two angles of a triangle, then the third angle is
`pi/4`
`(3pi)/4`
`pi/6`
`pi/3`
Choose the correct alternative:
`sin^-1 (tan pi/4) - sin^-1 (sqrt(3/x)) = pi/6`. Then x is a root of the equation
x2 – x – 6 = 0
x2 – x – 12 = 0
x2 + x – 12 = 0
x2 + x – 6 = 0
Choose the correct alternative:
sin–1(2 cos2x – 1) + cos–1(1 – 2 sin2x) =
`pi/2`
`pi/3`
`pi/4`
`pi/6`
Choose the correct alternative:
If `cot^-1(sqrt(sin alpha)) + tan^-1(sqrt(sin alpha))` = u, then cos 2u is equal to
tan2α
0
– 1
tan 2α
Choose the correct alternative:
If |x| ≤ 1, then `2tan^-1x - sin^-1 (2x)/(1 + x^2)` is equal to
tan–1x
sin–1x
0
π
Choose the correct alternative:
The equation tan–1x – cot–1x = `tan^-1 (1/sqrt(3))` has
no solution
unique solution
two solutions
infinite number of solutions
Choose the correct alternative:
If `sin^-1x + cot^-1 (1/2) = pi/2`, then x is equal to
`1/2`
`1/sqrt(5)`
`2/sqrt(5)`
`sqrt(3)/5`
Choose the correct alternative:
If `sin^-1x + "cosec"^-1 5/4 = pi/2`, then the value of x is
4
5
2
3
Choose the correct alternative:
sin(tan–1x), |x| < 1 is equal to
`x/sqrt(1 - x^2)`
`1/sqrt(1 - x^2)`
`1/sqrt(1 + x^2)`
`x/sqrt(1 + x^2)`
Solutions for 4: Inverse Trigonometric Functions
![Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board chapter 4 - Inverse Trigonometric Functions Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board chapter 4 - Inverse Trigonometric Functions - Shaalaa.com](/images/mathematics-volume-1-and-2-english-class-12-tn-board_6:5f2b1b2038084cf381bfa42c826a928c.jpg)
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 12 TN Board chapter 4 - Inverse Trigonometric Functions
Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Mathematics - Volume 1 and 2 [English] Class 12 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Mathematics - Volume 1 and 2 [English] Class 12 TN Board Tamil Nadu Board of Secondary Education 4 (Inverse Trigonometric Functions) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Mathematics - Volume 1 and 2 [English] Class 12 TN Board chapter 4 Inverse Trigonometric Functions are Some Fundamental Concepts, Sine Function and Inverse Sine Function, The Cosine Function and Inverse Cosine Function, The Tangent Function and the Inverse Tangent Function, The Cosecant Function and the Inverse Cosecant Function, The Secant Function and Inverse Secant Function, The Cotangent Function and the Inverse Cotangent Function, Principal Value of Inverse Trigonometric Functions, Properties of Inverse Trigonometric Functions, Inverse Trigonometric Functions.
Using Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board solutions Inverse Trigonometric Functions exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Mathematics - Volume 1 and 2 [English] Class 12 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.
Get the free view of Chapter 4, Inverse Trigonometric Functions Mathematics - Volume 1 and 2 [English] Class 12 TN Board additional questions for Mathematics Mathematics - Volume 1 and 2 [English] Class 12 TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.