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प्रश्न
Find the principal value of `sec^-1 (2/sqrt(3))`
उत्तर
Let `sec^-1 (2/sqrt(3))` = θ
⇒ sec θ = `2/sqrt(3)`
⇒ cos θ = `sqrt(3)/2`
= `cos pi/6`
⇒ θ = `pi/6`
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