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प्रश्न
Find the value of `cos[cos^-1 (4/5) + sin^-1(4/5)]`
उत्तर
`cos[cos^-1 (4/5) + sin^-1(4/5)]`
We know that `sin^-1x + cos^-1x = pi/2`
`cos[cos^-1 (4/5) + sin^-1(4/5)] = cos pi/2`` = 0
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