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प्रश्न
Find the value of `cos^-1(1/2) + sin^-1( - 1)`
उत्तर
x = `cos^-1(1/2)`
cos x = `1/2 = cos pi/3`
x = `pi/3`
y = `sin^-1 (- 1)`
sin y = `- 1 = sin(- pi/2)`
y = `- pi/2`
`cos^-1(1/2) + sin^-1( - 1) = pi/3 pi/2`
= `(2pi - 3pi)/6`
= `- pi/6`
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