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प्रश्न
Find the value of `cos^-1(cos((4pi)/3)) + cos^-1 (cos((5pi)/4))`
उत्तर
`cos^-1 (cos (4pi)/3) + cos^-1 (cos (5pi)/4)`
`(4pi)/3 ∈ [0, pi], (5pi)/4 ∈ [0, pi]`
`cos^-1[cos(pi+pi/3)]+cos^-1[cos(pi+pi/4)]`
`cos^-1[-cos (pi)/3]+cos^-1[-cos (pi)/4]`
`cos^-1[-1/2]+cos^-1[-1/2]`
x = `cos^-1(-1/2)`
cosx = `-1/2`
`(2pi)/3+(3pi)/4`
= `(8pi + 9pi)/12`
= `(17pi)/12`
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