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प्रश्न
Find the value of `tan(cos^-1 (1/2) - sin^-1 (- 1/2))`
बेरीज
उत्तर
`tan(cos^-1 (1/2) - sin^-1 (- 1/2))`
= `tan(cos^-1 1/2 + sin^-1 1/2)` ......`[because sin^-1 (- x) = - sin^-1x]`
= `tan (pi/2) = oo` .......`[because sin^-1x + cos^-1x = pi/2]`
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The Tangent Function and the Inverse Tangent Function
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.3 [पृष्ठ १४८]
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