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प्रश्न
Find the real roots of x4 = 16
बेरीज
उत्तर
x4 = 16
⇒ x4 – 16 = 0
(i.e.,) x4 – 42 = 0
⇒ (x2 + 4)(x2 – 4) = 0
x2 + 4 = 0 will have no real roots
So solving x2 – 4 = 0
x2 = 4
x = `+- sqrt(4)`
= `+- sqrt(2)`
So the real roots are x = ± 2
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