Advertisements
Advertisements
प्रश्न
Find the solution set of the inequation x + 5 < 2 x + 3 ; x ∈ R Graph the solution set on the number line.
उत्तर
x + 5 ≤ 2x + 3
x – 2x ≤ 3 – 5
⇒ -x ≤ -2
⇒ x ≥ 2
∵ x ∈ R
∴ Solution set = {2, 3, 4, 5, ......}
Solution set on number line
APPEARS IN
संबंधित प्रश्न
Represent the following inequalities on real number line:
8 ≥ x > – 3
Solve the following inequation and represent the solution set on the number line 2x – 5 ≤ 5x + 4 < 11, where x ∈ I.
Solve:
`x/2 + 5 <= x/3 + 6`, where x is a positive odd integer
Solve the following inequation and represent the solution set on the number line:
`-3 < -1/2 - (2x)/3 ≤ 5/6, x ∈ R`
Solve the following in equation and write the solution set:
13x – 5 < 15x + 4 < 7x + 12, x ∈ R
Solve the following inequation and graph the solution on the number line.
`-2(2)/(3) ≤ x + (1)/(3) < 3(1)/(3); x ∈ "R"`
Solve the following inequalities and represent the solution set on a number line:
`0 ≤ (3 - 2x)/(4) ≤ 1`
If x ∈ Z, solve 2 + 4x < 2x – 5 ≤ 3x. Also represent its solution on the number line.
Solve `(3x)/(5) - (2x - 1)/(3)` > 1, x ∈ R and represent the solution set on the number line.
A = {x : 11x – 5 > 7x + 3, x ∈R} and B = {x : 18x – 9 ≥ 15 + 12x, x ∈R}. Find the range of set A ∩ B and represent it on a number line
