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प्रश्न
Find the sum of the following expressions
7p + 6q, 5p – q, q + 16p
उत्तर
(7p + 6q) + (5p – q) + (q + 16p) = 7p + 6q + 5p – q + q + 16p
= (7p + 5p + 16p) + (6q – q + q)
= (7 + 5 + 16)p + (6 – 1 + 1)q
= (12 + 16)p + 6q
= 28p + 6q
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संबंधित प्रश्न
Simplify combining like terms: p − (p − q) − q − (q − p)
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What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?
Subtract:
\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]
Subtract:
\[\frac{ab}{7} - \frac{35}{3}bc + \frac{6}{5}ac \text { from } \frac{3}{5}bc - \frac{4}{5}ac\]
If \[x + \frac{1}{x} = 20,\]find the value of \[x^2 + \frac{1}{x^2} .\].
Add:
9p + 16q; 13p + 2q
Add:
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Find the expression to be added with 5a – 3b – 2c to get a – 4b – 2c?