Advertisements
Advertisements
प्रश्न
Find the sum of the following series
1 + 4 + 9 + 16 + ... + 225
उत्तर
1 + 4 + 9 + 16 + ... + 225
= 12 + 22 + 32 + 42 + ... + 152
`sum_1^"n" "n"^2 = ("n"("n" + 1)(2"n" + 1))/6`
`sum_1^15 "n"^2 = (15(15 + 1)(2 xx 15 + 1))/6`
= `(15 xx 16 xx 31)/6`
= 1240
APPEARS IN
संबंधित प्रश्न
Find the sum of the following series
3 + 6 + 9 + ... + 96
Find the sum of the following series
51 + 52 + 53 + ... + 92
Find the sum of the following series
62 + 72 + 82 + ... + 212
Find the sum of the following series
1 + 3 + 5 + ... + 71
If 1 + 2 + 3 + ... + k = 325, then find 13 + 23 + 33 + ... + k3
Rekha has 15 square colour papers of sizes 10 cm,11 cm,12 cm, …, 24 cm. How much area can be decorated with these colour papers?
Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to n terms
Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to 8 terms
The value of (13 + 23 + 33 + ... + 153) – (1 + 2 + 3 + ... + 15) is
The value of a motorcycle depreciates at a rate of 15% per year. What will be the value of the motorcycle for 3 year hence, which is now purchased for ₹ 45,000?
