Question

Find the value, if sin^–1x = y, then `->`:-

पर्याय

• `0 ≤ y ≤ pi`

• `- pi/2 ≤ y ≤ pi/2`

• O dot y dot

• `- pi/2 < y < pi/2`

Answer 1

`- pi/2 ≤ y ≤ pi/2`

Explanation:

If is given that sin^–1x = y

Range of the Principal value of sin^–1x is `[- pi/2, pi/2]`

Thus, `- pi/2 ≤ y ≤ pi/2`