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प्रश्न
Find the value of (3−1 + 4−1 + 5−1)0
बेरीज
उत्तर
(3−1 + 4−1 + 5−1)0
= `(1/3 + 1/4 + 1/5)^0` ...`[∵ a^-m = 1/a^m]`
= `((20 + 15 + 12)/60)^0`
= `(47/60)^0`
= 1 ....[∵ a0 = 1]
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