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प्रश्न
Find the value of ‘a’, if the line through (– 2, 3) and (8, 5) is perpendicular to y = ax + 2
उत्तर
Given points are (– 2, 3) and (8, 5)
Slope of a line = `(y_2 - y_1)/(x_2 - x_1)`
= `(5 - 3)/(8 + 2)`
= `2/10`
= `1/5`
Slope of a line y = ax + 2 is “a”
Since two lines are ⊥r
m1 × m2 = – 1
`1/5 xx "a"` = – 1
⇒ `"a"/5` = – 1
⇒ a = – 5
∴ The value of a = – 5
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