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Find the equation of a straight line passing through the mid-point of a line segment joining the points (1, – 5), (4, 2) and parallel to X-axis - Mathematics

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प्रश्न

Find the equation of a straight line passing through the mid-point of a line segment joining the points (1, – 5), (4, 2) and parallel to X-axis

बेरीज

उत्तर

Mid point of the line joining to points (1, – 5), (4, 2)

Mid point of the line = `((x_1 + x_2)/2, (y_1 + y_2)/2)`

= `((1 + 4)/2, (-5 + 2)/2)`

= `(5/2, (-3)/2)`

Any line parallel to X-axis. Slope of a line is 0.

Equation of a line is y – y1 = m (x – x1)

`y + 3/2 = 0(x - 5/2)`

`y + 3/2 = 0`

⇒ `(2y + 3)/2` = 0

2y + 3 = 0

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Straight Line
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पाठ 5: Coordinate Geometry - Exercise 5.3 [पृष्ठ २२९]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 5 Coordinate Geometry
Exercise 5.3 | Q 1. (i) | पृष्ठ २२९
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