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Question
Find the equation of a straight line passing through the mid-point of a line segment joining the points (1, – 5), (4, 2) and parallel to X-axis
Solution
Mid point of the line joining to points (1, – 5), (4, 2)
Mid point of the line = `((x_1 + x_2)/2, (y_1 + y_2)/2)`
= `((1 + 4)/2, (-5 + 2)/2)`
= `(5/2, (-3)/2)`
Any line parallel to X-axis. Slope of a line is 0.
Equation of a line is y – y1 = m (x – x1)
`y + 3/2 = 0(x - 5/2)`
`y + 3/2 = 0`
⇒ `(2y + 3)/2` = 0
2y + 3 = 0
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