Advertisements
Advertisements
प्रश्न
Find the equation of a straight line passing through the mid-point of a line segment joining the points (1, – 5), (4, 2) and parallel to Y-axis
उत्तर
Mid point of the line joining to points (1, – 5), (4, 2)
Mid point of the line = `((x_1 + x_2)/2, (y_1 + y_2)/2)`
= `((1 + 4)/2, (-5 + 2)/2)`
= `(5/2, (-3)/2)`
Equation of a line parallel to Y-axis is x = `5/2`
⇒ 2x = 5
2x – 5 = 0
APPEARS IN
संबंधित प्रश्न
The equation of a straight line is 2(x – y) + 5 = 0. Find its slope, inclination and intercept on the Y-axis
The hill in the form of a right triangle has its foot at (19, 3). The inclination of the hill to the ground is 45°. Find the equation of the hill joining the foot and top.
Find the equation of a straight line which has slope `(−5)/4` and passing through the point (– 1, 2).
You are downloading a song. The percent y (in decimal form) of megabytes remaining to get downloaded in x seconds is given by y = – 0.1x + 1 after how many seconds will 75% of the song gets downloaded?
Find the equation of a line whose intercepts on the x and y axes are given below
4, – 6
Find the equation of a straight line passing through (1, – 4) and has intercepts which are in the ratio 2 : 5
Find the equation of a straight line passing through (– 8, 4) and making equal intercepts on the coordinate axes
The point of intersection of 3x – y = 4 and x + 7 = 8 is
If A is a point on the Y-axis whose ordinate is 8 and B is a point on the X-axis whose abscissae is 5 then the equation of the line AB is
(2, 1) is the point of intersection of two lines