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प्रश्न
Find the value of the polynomial f(y) = 6y – 3y2 + 3 at y = 1
उत्तर
When y = 1
f(y) = 6y – 3y2 + 3
f(1) = 6(1) – 3(1)2 + 3
= 6 – 3 + 3
= 6
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