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प्रश्न
Find the values of following polynomials at m = 1, n = –1 and p = 2:
m2n2 + n2p2 + p2m2
उत्तर
Given, m = 1, n = –1 and p = 2
So, putting m = 1, n = –1 and p = 2 in the given expressions, we get
m2n2 + n2p2 + p2m2 = (1)2(–1)2 + (–1)2(2)2 + (2)2(1)2
= 1 + 4 + 4
= 9
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