Advertisements
Advertisements
प्रश्न
Find the values of following polynomials at m = 1, n = –1 and p = 2:
m2n2 + n2p2 + p2m2
उत्तर
Given, m = 1, n = –1 and p = 2
So, putting m = 1, n = –1 and p = 2 in the given expressions, we get
m2n2 + n2p2 + p2m2 = (1)2(–1)2 + (–1)2(2)2 + (2)2(1)2
= 1 + 4 + 4
= 9
APPEARS IN
संबंधित प्रश्न
Classify into monomials, binomials and trinomials.
x + y − xy
Expand −2p(5p2 – 3p + 7)
Find the product of 3(x – 5) × 2(x – 1)
An algebraic expression containing three terms is called a ______.
On adding a monomial ______ to –2x + 4y2 + z, the resulting expression becomes a binomial.
`1 + x/2 + x^3` is a polynomial.
If we subtract a monomial from a binomial, then answer is at least a binomial.
Write the following statements in the form of algebraic expressions and write whether it is monomial, binomial or trinomial.
Perimeter of an equilateral triangle of side x.
Find the values of the following polynomials at a = –2 and b = 3:
`(a^2 - b^2)/3`
Find the values of following polynomials at m = 1, n = –1 and p = 2:
mn + np + pm
