Advertisements
Advertisements
प्रश्न
Find whether the following equation have real roots. If real roots exist, find them.
5x2 – 2x – 10 = 0
उत्तर
Given equation is 5x2 – 2x – 10 = 0
On company with ax2 + bx + c = 0, we get
a = 5, b = – 2 and c = – 10
∴ Discriminant, D = b2 – 4ac
= (–2)2 – 4(5)(–10)
= 4 + 200
= 204 > 0
Therefore, the equation 5x2 – 2x – 10 = 0 has two distinct real roots.
Roots, `x = (-b +- sqrt(D))/(2a)`
= `(-(-2) +- sqrt(204))/(2 xx 5)`
= `(2 +- 2sqrt(51))/10`
= `(1 +- sqrt(51))/5`
= `(1 + sqrt(51))/5, (1 - sqrt(51))/5`
APPEARS IN
संबंधित प्रश्न
Solve for x : ` 2x^2+6sqrt3x-60=0`
If `x=2/3` and x =−3 are roots of the quadratic equation ax2 + 7x + b = 0, find the values of a and b.
Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:
`3x^2 - 4sqrt3x + 4 = 0`
If the roots of the equations ax2 + 2bx + c = 0 and `bx^2-2sqrt(ac)x+b = 0` are simultaneously real, then prove that b2 = ac.
Determine the nature of the roots of the following quadratic equation :
(x - 1)(2x - 7) = 0
Find the value(s) of k for which each of the following quadratic equation has equal roots: 3kx2 = 4(kx – 1)
Complete the following activity to find the value of discriminant for quadratic equation 4x2 – 5x + 3 = 0.
Activity: 4x2 – 5x + 3 = 0
a = 4 , b = ______ , c = 3
b2 – 4ac = (– 5)2 – (______) × 4 × 3
= ( ______ ) – 48
b2 – 4ac = ______
If the equation x2 – (2 + m)x + (–m2 – 4m – 4) = 0 has coincident roots, then:
A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.
Find the roots of the quadratic equation by using the quadratic formula in the following:
5x2 + 13x + 8 = 0